Hurricane Katrina, at 12:00 UTC, August 28, 2005.
Hurricane Katrina was a category 5 storm, there being only three other category five storms to hit the US in recorded history.
United States Naval Research Laboratory GOES-12 Satellite image no. 050828-N-0000W-002, via Wikimedia Commons
My maternal grandmother, shown here in her wedding photo, was born in 1895, more than a decade before the Wright Brothers made their first flight on December 17, 1903.
She lived to see Neil Armstrong walk on the Moon on July 21, 1969.
where m is the mass of the falling object, g is the gravitational acceleration (9.8 m/s/s), Cd is the drag coefficient (0.47 for a sphere), ρ is the fluid density (about 0.00125 g/cc for room temperature air), and A is the projected area of the object (πr2 for a sphere when r is the radius). Raindrops have a typical diameter of 1.5 mm, and water has a density of about 1 g/cc, so these parameters are easily calculated:
drop radius = 0.00075 mFor a particular rainfall rate, it's easy to calculate the density of water droplets ρr in the air during a rainstorm.
projected area = 1.767E-06 m2
volume = 1.767E-09 m3
mass = 0.001767 g
g = 9.8 m/s/s
ρ = 1250 g/m3
Cd = 0.47
Vt = 5.776 m/sec
Rainfall rate = 1.00 inch/hrNow that we have the physical properties of rainfall worked out, we need to know the affected surface areas of a person. If you're walking into the rain, you're collecting water on your frontal area, and when you're standing in the rain, you're collecting water on the area of your head, shoulders, and a little abdomen and backside bulge. To get an estimate of frontal area, I went to a classical source; namely, Leonardo da Vinci's Vitruvian Man, shown in a simplified form below.
Rainfall rate = 2.54 cm/hr
Rainfall volume = 25400 ml/m2/hr
Rainfall mass = 7.06 g/m2/sec
velocity = 5 m/sec
ρr= 1.4 g/m3
Leonardo da Vinci's Vitruvian Man (1492) in a simplified form.
From the collection of the Gallerie dell'Accademia (Venice, Italy). Photo by Luc Viatour, via Wikimedia Commons.
I checked the frontal area of this 15th century idealized man with a modern example from NASA.[5] NASA, of course, is very concerned with how its astronauts fit into their space suits, seats, and spacecraft. Doing this same image processing with an image on its website gave a frontal area for a man of 911 square inches = 0.587741 square meters, which is quite close. For my calculations, I used a frontal area of 0.6 square meters. Likewise, using NASA data, I created a rough model of the top area of a standing man, as shown. Image analysis gave an area of 0.0965 square meters.
Now, we have all the data we need for the simulation, which I programmed in the Gnumeric spreadsheet application (Gnumeric source here. *.xls file for MS Exel or LibreOffice, here). The principle of the simulation is simple - The longer you're in the rain, the more water falls on top of you; but, no matter what your travel rate is, you still soak up all the water in the corridor between your starting point and your destination.
The simulation is for 500 meters travel at rates of 0.25 - 5.75 meters/second in a one-inch-per-hour rainfall. As you can see from the graph, walking at 1.4 meters per second doesn't get you that much wetter than running at 5.75 meters per second. All this presumes that you're not wearing any rain gear, and you, and your clothing, are perfectly absorbent.
Walk, don't run.
A normal walking pace is 1.4 meters per second. Running, rather than walking, in the rain doesn't make you much less wet.
(Graphed using Gnumeric)